Table 3

Example 4: Comparison of absolute errors of our scheme with scheme in [42, 43]

Method of [42]Method of [43]The presented method
xα = 1.2α = 1.5α = 1.8α = 1.2α = 1.5α = 1.8α = 1.2α = 1.5α = 1.8
0.21.54 e-123.78 e-114.34 e-111.61 e-31.42 e-37.24 e-40.1055e-120.9843e-121.9413e-12
0.41.44 e-108.64 e-111.37 e-101.42 e-31.02 e-35.74 e-41.47905e-123.9820e-122.3070e-12
0.61.63 e-101.54 e-101.48 e-108.75 e-47.49 e-44.12 e-43.3255e-125.0410e-129.1279e-13
0.81.30 e-102.10 e-101.55 e-107.50 e-46.16 e-43.22 e-41.1055e-123.0410e-122.3986e-12
1.01.89 e-102.21 e-102.19 e-107.13 e-45.76 e-42.95 e-42.1152e-121.0010e-128.3765e-12
1.22.48 e-101.94 e-102.53 e-107.50 e-46.16 e-43.22 e-47.0055e-121.0410e-135.1819e-12
1.41.73 e-101.51 e-101.74 e-108.75 e-47.49 e-44.12 e-41.3498e-121.2430e-122.2781e-12
1.65.11 e-119.89 e-116.21 e-111.42 e-31.02 e-35.74 e-46.245e-123.0410e-125.2410e-12
1.83.43 e-113.72 e-113.08 e-111.61 e-31.42 e-37.24 e-41.1055e-133.0410e-121.3452e-12

or Create an Account

Close subscription notice
Close access options