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Let E be an elliptic curve with Weierstrass form y2=x3px, where p is a prime number and let E[m] be its m-torsion subgroup. Let p1=(x1,y1) and p2=(x2,y2) be a basis for E[m], then we prove that (E[m])=(x1,x2,ξm,y1) in general. We also find all the generators and degrees of the extensions (E[m])/ for m=3 and m=4.

Let E be an elliptic curve with Weierstrass form y2=x3px, where p is a prime number. Let m be a positive number, we denote by E[m] the m -torsion subgroup of E, by (E[m]) the number field generated by the coordinates of the m -torsion points of E, and by (Ex[m]) the number field generated by the abscissas of m -torsion points of E. Mazur proves the m -torsion subgroup is isomorphic to one of 15 finite groups [5]. Let p1=(x1,y1) and p2=(x2,y2) be two points in E forming a basis of E[m], then (E[m])=(x1,x2,y1,y2). By Artin’s primitive element theorem the extension (x1,x2,y1,y2)/ is monogeneous and we can find unique generator for (x1,x2,y1,y2)/ by combining the above coordinates. As usual, we denote by μm the group of mth roots of unity and by ξm one of its generators. By Weil pairing, we have ξm(E[m]), so (ξm)(E[m]) for all m [5]. In [3] Paladino gives a family of elliptic curves such that (E[3])=(ξ3) and in [4] finds the number fields generated by the 4th torsion points, degrees and Galois groups of an elliptic curve y2=(xα)(xβ)(xγ) where α,β,γ, and αβγ. In [1] Bandini and Paladino determine the number fields generated by the 3-torsion points, degrees and Galois groups of an elliptic curve y2=x3+c where c. In [2] the result of Brau and Jones says that the rational points on the modular curve of level 6 yield elliptic curve E satisfying the given containment. In the first part of this paper we prove ξm(Ex[m]) and (E[m])=(x1,x2,ξm,y1) for all m. In the second part of this paper we find the number fields of torsion points E[m] for cases m=3,4, extensions and degrees. These theorems have applications in local–global divisibility problem [4] and modular curves [2].

Let p1=(x1,y1) and p2=(x2,y2) form a basis of E[m]. We have (E[m])=(x1,x2,y1,y2). We will denote by L the field (x1,x2) and by K the field (E[m]). Suppose (x3,y3) be the coordinates of the point p3=p1+p2 and (x4,y4) be the coordinates of the point p4=p1p2. In next theorem we will prove ξm(Ex[m]) for all m.

Lemma 2.1.Let{P,Q}be a basis forE[m]. Thenem(P,Q)is a primitivemth root of unity.

Proof. We know that there are S,TE[m] such that em(S,T)=ξm, a primitive mth root of unity. Write S=aP+bQ and T=cP+dQ. Then the antisymmetry properties of the Weil pairing imply that

Since em(P,Q) is an mth root of unity and a power of it is a primitive mth root of unity, it follows that em(P,Q) is a primitive mth root of unity.□

Theorem 2.2.Let{p1,p2}be a basis forE[m], letp3=p1+p2andp4=p1p2, and writepi=(xi,yi). Then

Proof. The second inclusion is by the definition of (Ex[m]). For the first inclusion. Let σ be an automorphism of (E[m]) that fixes (x1,x2,x3,x4). Then σ(yi)=±yi since σ(yi2)=yi2. The equation

shows that σ(y1y2)=y1y2. This means that either σ(yi)=yi for i=1,2, or σ(yi)=yi for i=1,2. These mean that either σ(pi)=pi for i=1,2, or σ(pi)=pi for i=1,2. In the first case,

In the second case,

Since em(p1,p2) is a primitive mth root of unity, we find that (ξm)(x1,x2,x3,x4).□

We know that (x1,x2,y1,y2)=(x1,x2,y1,y1y2). In next theorem we will prove that (E[m]) is equal to the field (x1,x2) by adding ξm and y1.

Theorem 2.3.

(E[m])=(x1,x2,ξm,y1).

Proof. We have (x1,x2,ξm,y1,y2)=(E[m]). If we do not have the equality in the theorem, then y2(x1,x2,ξm,y1). Since y22 is in this field, there is an automorphism σ such that σ(y2)=y2 and σ is the identity on (x1,x2,ξm,y1). Then

This implies that em(p1,p2)2=1. Since em(p1,p2) is a primitive mth root of unity, we must have m=2. But then y1=y2=0, in which case the theorem is true.□

It is well known that the abscissas of the 3-torsion points of an elliptic curve y2=x3px are the roots of the polynomial

then the roots x1^,x2^,x3^,x4^ of ϕ3 are:

In next theorems we will determine the field generated by 3 and 4 torsion points.

Theorem 3.1.LetEbe an elliptic curve with Weierstrass formE:y2=x3px, wherepis a prime number. Then

Proof. We have (x1^,x2^,x3^,x4^)=(x1^,x3^). On the other hand we have

so (x1^,x3^)=(x1^,x1^x3^)=(x1^,ξ3)=(p2p3,ξ3).

We have

Put α=p2p3, then

is irreducible over (ξ3), because the roots of f(x) are x1^,x2^,x3^,x4^. They are irrational, so either f(x) is irreducible or it has a quadratic factor that has x1^ and some other xi^ as roots. Since x1^x2^(ξ3), the other root is not x2^. Suppose the other root is x3^ or x4^. Then (using x3^)

is a square in (ξ3). But its norm to is 16p23, which is not a square, so it cannot be a square. Therefore, there is no quadratic factor and f(x) is irreducible. So [(p2p3,ξ3):(ξ3)]=4. It is easy to verify that [(ξ3):]=2. Hence

By Theorem 2.2 we proved that (E[3])=(x1^,x2^,ξ3,y1^)=(x1^,ξ3,y1^), where x1^=x2^. As y1^2=x1^3px1^, then

and [(x1^,ξ3,y1^):(x1^,ξ3)]=2. We found in previous case that [(x1^,ξ3):]=8.

Hence

It is well known that the abscissas of the 4-torsion points of an elliptic curve y2=x3px are the roots of the polynomial

then the roots x1^,x2^,x3^,x4^,x5^,x6^ of ϕ4 are

Theorem 3.2.LetEbe an elliptic curve with Weierstrass formy2=x3px, wherepis a prime number. Then

Proof. The points of exact order 4 of y2=x3px are ±p1,±p2,±p3,±p4,±p5,±p6, where

We have:

with [(Ex[4]):]=8 if p2 and [(Ex[4]):]=4 if p=2.□

Let {p1,p2} be a basis for E[4], then

with [(E[4]):]=16 if p2 and [(E[4]):]=[(i,84)]=8 if p=2.□

Declaration of Competing Interest: The authors declare that they have no known competing financial interests or personal relationships that could have appeared to influence the work reported in this paper. The publisher wishes to inform readers that the article “Generators and number fields for torsion points of a special elliptic curve” was originally published by the previous publisher of the Arab Journal of Mathematical Sciences and the pagination of this article has been subsequently changed. There has been no change to the content of the article. This change was necessary for the journal to transition from the previous publisher to the new one. The publisher sincerely apologises for any inconvenience caused. To access and cite this article, please use Sankari, H., Bojakli, M. (2019), “Generators and number fields for torsion points of a special elliptic curve”, Arab Journal of Mathematical Sciences, Vol. 26 No. 1/2, pp. 227-231. The original publication date for this paper was 29/10/2019

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Published in the Arab Journal of Mathematical Sciences. Published by Emerald Publishing Limited. This article is published under the Creative Commons Attribution (CC BY 4.0) license. Anyone may reproduce, distribute, translate and create derivative works of this article (for both commercial and non-commercial purposes), subject to full attribution to the original publication and authors. The full terms of this license may be seen at http://creativecommons.org/licences/by/4.0/legalcode

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