Let be an elliptic curve with Weierstrass form where is a prime number and let be its -torsion subgroup. Let and be a basis for , then we prove that in general. We also find all the generators and degrees of the extensions for and .
1. Introduction
Let be an elliptic curve with Weierstrass form , where is a prime number. Let be a positive number, we denote by the -torsion subgroup of , by the number field generated by the coordinates of the -torsion points of , and by the number field generated by the abscissas of -torsion points of . Mazur proves the -torsion subgroup is isomorphic to one of 15 finite groups [5]. Let and be two points in forming a basis of , then . By Artin’s primitive element theorem the extension is monogeneous and we can find unique generator for by combining the above coordinates. As usual, we denote by the group of th roots of unity and by one of its generators. By Weil pairing, we have , so for all [5]. In [3] Paladino gives a family of elliptic curves such that and in [4] finds the number fields generated by the 4th torsion points, degrees and Galois groups of an elliptic curve where , and . In [1] Bandini and Paladino determine the number fields generated by the 3-torsion points, degrees and Galois groups of an elliptic curve where . In [2] the result of Brau and Jones says that the rational points on the modular curve of level yield elliptic curve satisfying the given containment. In the first part of this paper we prove and for all . In the second part of this paper we find the number fields of torsion points for cases , extensions and degrees. These theorems have applications in local–global divisibility problem [4] and modular curves [2].
2. Generators for
Let and form a basis of . We have . We will denote by the field and by the field . Suppose be the coordinates of the point and be the coordinates of the point . In next theorem we will prove for all .
Lemma 2.1. Let be a basis for . Then is a primitive th root of unity.
Proof. We know that there are such that , a primitive th root of unity. Write and . Then the antisymmetry properties of the Weil pairing imply that
Since is an th root of unity and a power of it is a primitive th root of unity, it follows that is a primitive th root of unity.□
Theorem 2.2. Let be a basis for , let and , and write . Then
Proof. The second inclusion is by the definition of . For the first inclusion. Let be an automorphism of that fixes . Then since . The equation
shows that . This means that either for , or for . These mean that either for , or for . In the first case,
In the second case,
Since is a primitive th root of unity, we find that .□
We know that . In next theorem we will prove that is equal to the field by adding and .
Theorem 2.3.
Proof. We have . If we do not have the equality in the theorem, then . Since is in this field, there is an automorphism such that and is the identity on . Then
This implies that . Since is a primitive th root of unity, we must have . But then , in which case the theorem is true.□
3. Number fields for cases m 3, 4
It is well known that the abscissas of the 3-torsion points of an elliptic curve are the roots of the polynomial
then the roots of are:
In next theorems we will determine the field generated by 3 and 4 torsion points.
Theorem 3.1. Let be an elliptic curve with Weierstrass form , where is a prime number. Then
Proof. We have . On the other hand we have
so .
We have
Put , then
is irreducible over , because the roots of are . They are irrational, so either is irreducible or it has a quadratic factor that has and some other as roots. Since , the other root is not . Suppose the other root is or . Then (using )
is a square in . But its norm to is , which is not a square, so it cannot be a square. Therefore, there is no quadratic factor and is irreducible. So . It is easy to verify that . Hence
By Theorem 2.2 we proved that , where . As , then
and . We found in previous case that .
Hence
It is well known that the abscissas of the 4-torsion points of an elliptic curve are the roots of the polynomial
then the roots of are
Theorem 3.2. Let be an elliptic curve with Weierstrass form , where is a prime number. Then
Proof. The points of exact order of are , where
We have:
with if and if .□
Let be a basis for , then
with if and if .□
Declaration of Competing Interest: The authors declare that they have no known competing financial interests or personal relationships that could have appeared to influence the work reported in this paper. The publisher wishes to inform readers that the article “Generators and number fields for torsion points of a special elliptic curve” was originally published by the previous publisher of the Arab Journal of Mathematical Sciences and the pagination of this article has been subsequently changed. There has been no change to the content of the article. This change was necessary for the journal to transition from the previous publisher to the new one. The publisher sincerely apologises for any inconvenience caused. To access and cite this article, please use Sankari, H., Bojakli, M. (2019), “Generators and number fields for torsion points of a special elliptic curve”, Arab Journal of Mathematical Sciences, Vol. 26 No. 1/2, pp. 227-231. The original publication date for this paper was 29/10/2019
